答表示

中3 因数分解 置き換え_1

次の式を因数分解せよ。
(x+y)a-(x+y)b
(x+y)(a-b)
(a+b)2+2(a+b)-15
(a+b+5)(a+b-3)
(x+y)2-a2
(x+y+a)(x+y-a)
a(x+3)-b(x+3)
(a-b)(x+3)
(x-2)2-6(x-2)+8
(x-4)(x-6)
(2a-b)2-6(2a-b)+9
(2a-b-3)2
(3x+5)2-(x-2)2
(4x+3)(2x+7)
(a-b)x2-3(a-b)x-40(a-b)
(a-b)(x-8)(x+5)
次の式を因数分解せよ。
a(x+1)-x-1
(x+1)(a-1)
(a+3)(a-4)+2a+6
(a+3)(a-2)
a(x-y)+2(y-x)
(x-y)(a-2)
(a+2)(a-b)-a+b
(a-b)(a+1)
(a-2b)2+5(2b-a)+6
(a-2b-2)(a-2b-3)
a(2x+1)2+a(2x+1)-12a
2a(2x+5)(x-1)
(3x-2y)2-(2x-3y)2
5(x-y)(x+y)
(x-4)2-3x+12
(x-4)(x-7)
(a2-3a)+2(3-a)
(a-2)(a-3)
解答 表示
(x+y)(a-b)
(a+b+5)(a+b-3)
(x+y+a)(x+y-a)
(a-b)(x+3)
(x-4)(x-6)
(2a-b-3)2
(4x+3)(2x+7)
(a-b)(x-8)(x+5)
(x+1)(a-1)
(a+3)(a-2)
(x-y)(a-2)
(a-b)(a+1)
(a-2b-2)(a-2b-3)
2a(2x+5)(x-1)
5(x-y)(x+y)
(x-4)(x-7)
(a-2)(a-3)
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