中2
加減法2 _2
連立方程式を解け
x+4y=7 3x-10y=-12
x=1, y=32
9x+y=2 15x+2y=3
x=13, y=-1
x-12y=-11 3x+16y=6
x=-2, y=34
5x-y=-3 11x+3y=-4
x=-12, y=12
3x-12y=5 6x+9y=-1
x=13, y=-13
2x-12y=-5 4x+20y=23
x=2, y=34
-7x+15y=-4 x-10y=-1
x=1, y=15
-6x+5y=20 3x-4y=-13
x=-53, y=2
連立方程式を解け
6x+15y=-8 5x-6y=18
x=2, y=-43
3x-6y=7 2x+9y=-4
x=1, y=-23
4x-3y=8 6x+8y=-13
x=12, y=-2
4x-12y=-15 7x+8y=-19
x=-3, y=14
-2x+8y=-7 10x+3y=-8
x=-12, y=-1
18x-6y=7 4x-9y=-1
x=12, y=13
-8x+6y=9 12x-8y=-11
x=34, y=52
-15x-18y=-20 9x+24y=34
x=-23, y=53
解答 表示
x=1, y=32
x=13, y=-1
x=-2, y=34
x=-12, y=12
x=13, y=-13
x=2, y=34
x=1, y=15
x=-53, y=2
x=2, y=-43
x=1, y=-23
x=12, y=-2
x=-3, y=14
x=-12, y=-1
x=12, y=13
x=34, y=52
x=-23, y=53